A block of wood floats in water with frac{4}{ | vedclass

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(B) Let $V_b$ be the volume of the block and $\rho_b$ be its density.When the block floats in water,the weight of the block equals the weight of the d

Vedclass · Accepted Answer

$800$

Vedclass · Answer

(B) Let $V_b$ be the volume of the block and $ho_b$ be its density.When the block floats in water,the weight of the block equals the weight of the displaced water:$V_b \cdot ho_b \cdot g = (\frac{4}{5} V_b) \cdot ho_w \cdot g$Given $ho_w = 1000 \, kg/m^3$,we have:$ho_b = \frac{4}{5} 	imes 1000 = 800 \, kg/m^3$.When the block 'just floats' in another liquid of density $ho_l$,it means the entire volume of the block is submerged:$V_b \cdot ho_b \cdot g = V_b \cdot ho_l \cdot g$Therefore,$ho_l = ho_b = 800 \, kg/m^3$.

$A$ block of wood floats in water with $\frac{4}{5}$ of its volume submerged,but it just floats in another liquid. The density of the liquid is (in $kg/m^3$):

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