A buffer solution can be prepared from a mixt | vedclass

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(D) The correct answer is $D$.$A$ buffer solution is prepared by mixing a weak acid with its conjugate base (salt of a strong base) or a weak base wit

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$A$ and $C$ both

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(D) The correct answer is $D$.$A$ buffer solution is prepared by mixing a weak acid with its conjugate base (salt of a strong base) or a weak base with its conjugate acid (salt of a strong acid).$1$. Sodium acetate $(CH_3COONa)$ and acetic acid $(CH_3COOH)$ form an acidic buffer because acetic acid is a weak acid and sodium acetate is its salt with a strong base $(NaOH)$.$2$. Ammonia $(NH_3)$ and ammonium chloride $(NH_4Cl)$ form a basic buffer because ammonia is a weak base and ammonium chloride is its salt with a strong acid $(HCl)$.$3$. Sodium acetate and hydrochloric acid $(HCl)$ react to form acetic acid and sodium chloride,which does not constitute a buffer system in the required proportions.Therefore,both $A$ and $C$ are correct.

$A$ buffer solution can be prepared from a mixture of

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$A$ buffer solution is a mixture of

The $pK_a$ of a weak acid is $4.8$. What should be the ratio of $\frac{[\text{acid}]}{[\text{salt}]}$, if a buffer of $pH = 5.8$ is required?

$2 \ g$ acetic acid and $3 \ g$ sodium acetate are present in $100 \ mL$ aqueous solution. What will be the $pH$ of the solution if the ionisation constant of acetic acid is $1.8 \times 10^{-5}$?

Which of the following solutions does not act as a buffer?

The $pK_a$ of a weak acid $(HA)$ is $4.5$. The $pOH$ of an aqueous buffer solution of $HA$ in which $50\%$ of the acid is ionized is

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