(B) The car requires a driver in the front seat. Since $2$ persons can drive,we must select $1$ driver from these $2$ people. This can be done in $^2C

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(B) The car requires a driver in the front seat. Since $2$ persons can drive,we must select $1$ driver from these $2$ people. This can be done in $^2C_1$ ways.After selecting the driver,we need to fill the remaining $2$ seats (one in the front and one in the rear) from the remaining $5$ people. This can be done in $^5C_2$ ways.Therefore,the total number of ways to fill the car is $^2C_1 \times ^5C_2 = 2 \times 10 = 20$.

Competitive Quantitative Aptitude Permutation and Combination Permutation and Combination

Medium

$A$ car can hold $2$ people in the front seat and $1$ person in the rear seat. If among $6$ persons $2$ can drive,then the number of ways in which the car can be filled is

A
$10$
B
$20$
C
$30$
D
None of these

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$A$ car can hold $2$ people in the front seat and $1$ person in the rear seat. If among $6$ persons $2$ can drive,then the number of ways in which the car can be filled is

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