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(B) Let $X$ be the number of heads obtained in $n$ tosses of a coin.$X$ follows a binomial distribution with parameters $n$ and $p = 1/2$.The probabil

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$3$

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(B) Let $X$ be the number of heads obtained in $n$ tosses of a coin.$X$ follows a binomial distribution with parameters $n$ and $p = 1/2$.The probability of getting at least one head is given by $P(X \ge 1) > 0.8$.We know that $P(X \ge 1) = 1 - P(X = 0)$.So,$1 - P(X = 0) > 0.8$,which implies $P(X = 0) The probability of getting zero heads in $n$ tosses is $P(X = 0) = ^nC_0 	imes (1/2)^n = (1/2)^n$.Thus,$(1/2)^n This simplifies to $2^n > 5$.For $n = 1$,$2^1 = 2 For $n = 2$,$2^2 = 4 For $n = 3$,$2^3 = 8 > 5$.Therefore,the least integer value of $n$ is $3$.

$A$ coin is tossed $n$ times. The probability of getting head at least once is greater than $0.8$,then the least value of $n$ is

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