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(C) The torque experienced by a magnetic dipole in a magnetic field is given by $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnet

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$30$

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(C) The torque experienced by a magnetic dipole in a magnetic field is given by $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnetic moment and the magnetic field.Here,the needle points towards geographical north,but the magnetic field is directed towards magnetic north. The angle $	heta$ between these two directions is the angle of declination.Given: $	au = 1.2 	imes 10^{-3} \ Nm$,$M = 60 \ Am^2$,$B_H = 40 	imes 10^{-6} \ T$.Using the formula: $\sin 	heta = \frac{	au}{M B_H}$.$\sin 	heta = \frac{1.2 	imes 10^{-3}}{60 	imes 40 	imes 10^{-6}} = \frac{1.2 	imes 10^{-3}}{2400 	imes 10^{-6}} = \frac{1.2 	imes 10^{-3}}{2.4 	imes 10^{-3}} = \frac{1.2}{2.4} = 0.5$.Therefore,$	heta = \arcsin(0.5) = 30^{\circ}$.

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