A complex current wave is given by i = 5 + 5 | vedclass

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Question

(B) The given current wave is $i = 5 + 5 \sin(100 \omega t)$.To find the average value over one time period $T$,we use the formula $\langle i \rangle

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$5$

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(B) The given current wave is $i = 5 + 5 \sin(100 \omega t)$.To find the average value over one time period $T$,we use the formula $\langle i angle = \frac{1}{T} \int_{0}^{T} i \, dt$.Substituting the expression for $i$:$\langle i angle = \frac{1}{T} \int_{0}^{T} (5 + 5 \sin(100 \omega t)) \, dt$.This can be split into two parts:$\langle i angle = \frac{1}{T} \int_{0}^{T} 5 \, dt + \frac{1}{T} \int_{0}^{T} 5 \sin(100 \omega t) \, dt$.The average value of a sine function over one complete cycle is $0$,i.e.,$\langle \sin(100 \omega t) angle = 0$.Therefore,$\langle i angle = 5 + 0 = 5 	ext{ A}$.

$A$ complex current wave is given by $i = 5 + 5 \sin(100 \omega t) \text{ A}$. Its average value over one time period is given as......$\text{A}$

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