A constant electric current I is passed throu | vedclass

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(B) The current $I$ in a conductor is given by $I = neAv_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is the c

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$\frac{Il}{S}$

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(B) The current $I$ in a conductor is given by $I = neAv_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is the cross-sectional area,and $v_d$ is the drift velocity.The total number of electrons $N$ in a conductor of length $l$ is $N = nAl$.The total momentum $P$ of the electrons is $P = Nmv_d$,where $m$ is the mass of an electron.Substituting $N = nAl$,we get $P = (nAl)mv_d$.From the current formula,$nAv_d = \frac{I}{e}$.Substituting this into the momentum equation: $P = l \cdot (nAv_d) \cdot m = l \cdot \frac{I}{e} \cdot m$.Since the specific charge $S$ is defined as the ratio of charge to mass,$S = \frac{e}{m}$,therefore $\frac{m}{e} = \frac{1}{S}$.Thus,the total momentum $P = \frac{Il}{S}$.

$A$ constant electric current $I$ is passed through a straight conductor of length $l$. If $S$ is the specific charge of an electron,then the total momentum of the electrons is:

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