A cylinder with radius 21 , cm and height 18 | vedclass

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Question

(A) The article consists of a cylinder and two hemispheres attached at both ends.Radius of the cylinder $(r)$ = $21 \, cm$.Height of the cylinder $(h)

Vedclass · Accepted Answer

$7920$

Vedclass · Answer

(A) The article consists of a cylinder and two hemispheres attached at both ends.Radius of the cylinder $(r)$ = $21 \, cm$.Height of the cylinder $(h)$ = $18 \, cm$.Radius of the hemispheres $(r)$ = $21 \, cm$.The total surface area of the article = (Curved surface area of the cylinder) + $2 	imes$ (Curved surface area of the hemisphere).Curved surface area of the cylinder = $2 \pi r h = 2 	imes \frac{22}{7} 	imes 21 	imes 18 = 2 	imes 22 	imes 3 	imes 18 = 2376 \, cm^2$.Curved surface area of two hemispheres = $2 	imes (2 \pi r^2) = 4 \pi r^2 = 4 	imes \frac{22}{7} 	imes 21 	imes 21 = 4 	imes 22 	imes 3 	imes 21 = 5544 \, cm^2$.Total surface area = $2376 + 5544 = 7920 \, cm^2$.

$A$ cylinder with radius $21 \, cm$ and height $18 \, cm$ is closed at both the ends by hemispheres. Find the surface area of this article. $(\pi = \frac{22}{7})$ (in $cm^2$)

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