Two identical cubes each of volume 64 , cm^{3 | vedclass

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(D) Let the side length of a cube be $a \, cm$.Given,the volume of the cube is $a^{3} = 64 \, cm^{3}$.Therefore,$a = \sqrt[3]{64} = 4 \, cm$.When two

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$160$

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(D) Let the side length of a cube be $a \, cm$.Given,the volume of the cube is $a^{3} = 64 \, cm^{3}$.Therefore,$a = \sqrt[3]{64} = 4 \, cm$.When two such cubes are joined end to end,they form a cuboid with dimensions:Length $(l)$ = $2a = 2 	imes 4 = 8 \, cm$Breadth $(b)$ = $a = 4 \, cm$Height $(h)$ = $a = 4 \, cm$The surface area of the resulting cuboid is given by the formula $2(lb + bh + hl)$.Surface Area = $2(8 	imes 4 + 4 	imes 4 + 4 	imes 8)$Surface Area = $2(32 + 16 + 32)$Surface Area = $2(80) = 160 \, cm^{2}$.

Two identical cubes each of volume $64 \, cm^{3}$ are joined together end to end. What is the surface area of the resulting cuboid? (in $cm^{2}$)

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