$A$ die is thrown $1000$ times with the frequencies for the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:
Outcome $1$ $2$ $3$ $4$ $5$ $6$ Frequency $179$ $150$ $157$ $149$ $175$ $190$
Find the probability of getting each outcome.
| Outcome | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| Frequency | $179$ | $150$ | $157$ | $149$ | $175$ | $190$ |
Find the probability of getting each outcome.
(N/A) Let $E_i$ denote the event of getting the outcome $i$,where $i = 1, 2, 3, 4, 5, 6$.
The probability of an event is given by the formula: $P(E) = \frac{\text{Number of trials in which the event happened}}{\text{Total number of trials}}$.
Here,the total number of trials is $1000$.
$P(E_1) = \frac{179}{1000} = 0.179$
$P(E_2) = \frac{150}{1000} = 0.150$
$P(E_3) = \frac{157}{1000} = 0.157$
$P(E_4) = \frac{149}{1000} = 0.149$
$P(E_5) = \frac{175}{1000} = 0.175$
$P(E_6) = \frac{190}{1000} = 0.190$
Note that the sum of all probabilities is $0.179 + 0.150 + 0.157 + 0.149 + 0.175 + 0.190 = 1$.
The probability of an event is given by the formula: $P(E) = \frac{\text{Number of trials in which the event happened}}{\text{Total number of trials}}$.
Here,the total number of trials is $1000$.
$P(E_1) = \frac{179}{1000} = 0.179$
$P(E_2) = \frac{150}{1000} = 0.150$
$P(E_3) = \frac{157}{1000} = 0.157$
$P(E_4) = \frac{149}{1000} = 0.149$
$P(E_5) = \frac{175}{1000} = 0.175$
$P(E_6) = \frac{190}{1000} = 0.190$
Note that the sum of all probabilities is $0.179 + 0.150 + 0.157 + 0.149 + 0.175 + 0.190 = 1$.
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