$A$ hydraulic press containing water has two arms with diameters as shown in the figure. $A$ force of $10 \,N$ is applied on the surface of water in the thinner arm. The force required to be applied on the surface of water in the thicker arm to maintain equilibrium of water is . . . . . . $N$.

$A$ hydraulic automobile lift is designed to lift cars with a maximum mass of $3000 \, kg$. The area of cross-section of the piston carrying the load is $425 \, cm^{2}$. What is the maximum pressure the smaller piston would have to bear?

In a car lift,compressed air exerts a force $F_{1}$ on a small piston having a radius of $5.0 \; cm$. This pressure is transmitted to a second piston of radius $15 \; cm$. If the mass of the car to be lifted is $1350 \; kg$,calculate $F_{1}$. What is the pressure necessary to accomplish this task? $(g = 9.8 \; m s^{-2})$

In a hydraulic lift,the surface area of the input piston is $6 \ cm^2$ and that of the output piston is $1500 \ cm^2$. If $100 \ N$ force is applied to the input piston to raise the output piston by $20 \ cm$,then the work done is . . . . . . $kJ$.

$A$ tall tank filled with water has an irregular shape as shown. The wall $CD$ makes an angle of $45^{\circ}$ with the horizontal,the wall $AB$ is normal to the base $BC$. The lengths $AB$ and $CD$ are much smaller than the height $h$ of water (figure not to scale). Let $p_1, p_2$ and $p_3$ be the pressures exerted by the water on the wall $AB$,base $BC$ and the wall $CD$ respectively. Density of water is $\rho$ and $g$ is acceleration due to gravity. Then,approximately

$A$ hydraulic automobile lift is designed to lift cars with a maximum mass of $3000 \; kg$. The area of cross-section of the piston carrying the load is $425 \; cm^{2}$. What maximum pressure would the smaller piston have to bear?