A man can row 44 text{ km} downstream in 4 te | vedclass

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(A) Let the speed of the current be $y 	ext{ km/hr}$.The speed downstream is given by the sum of the speed in still water and the speed of the curren

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(A) Let the speed of the current be $y 	ext{ km/hr}$.The speed downstream is given by the sum of the speed in still water and the speed of the current,which is $(8 + y) 	ext{ km/hr}$.Given that the man rows $44 	ext{ km}$ downstream in $4 	ext{ hours}$,we have:$	ext{Speed downstream} = \frac{	ext{Distance}}{	ext{Time}} = \frac{44 	ext{ km}}{4 	ext{ hr}} = 11 	ext{ km/hr}$.Equating the two expressions for downstream speed:$8 + y = 11 \Rightarrow y = 3 	ext{ km/hr}$.The speed upstream is given by the difference between the speed in still water and the speed of the current,which is $(8 - y) 	ext{ km/hr}$.Substituting $y = 3 	ext{ km/hr}$:$	ext{Speed upstream} = 8 - 3 = 5 	ext{ km/hr}$.Time taken to cover $25 	ext{ km}$ upstream is:$	ext{Time} = \frac{	ext{Distance}}{	ext{Speed upstream}} = \frac{25 	ext{ km}}{5 	ext{ km/hr}} = 5 	ext{ hours}$.

$A$ man can row $44 \text{ km}$ downstream in $4 \text{ hours}$. If the man's rowing rate in still water is $8 \text{ km/hr}$,then find in what time will he cover $25 \text{ km}$ upstream? (in $\text{hours}$)

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