A mixture contains alcohol and water in the r | vedclass

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Question

(D) Let the quantity of alcohol be $12x$ and water be $5x$.According to the problem,when $14 	ext{ litres}$ of water is added,the ratio becomes $4: 3

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Let the quantity of alcohol be $12x$ and water be $5x$.According to the problem,when $14 	ext{ litres}$ of water is added,the ratio becomes $4: 3$.So,$\frac{12x}{5x + 14} = \frac{4}{3}$.Cross-multiplying,we get $3 	imes 12x = 4 	imes (5x + 14)$.$36x = 20x + 56$.$36x - 20x = 56$.$16x = 56$.$x = \frac{56}{16} = 3.5$.The quantity of alcohol is $12x = 12 	imes 3.5 = 42 	ext{ litres}$.Since $42$ is not among the options,the correct answer is $D$ (None of these).

$A$ mixture contains alcohol and water in the ratio of $12: 5$. On adding $14 \text{ litres}$ of water,the ratio of alcohol to water becomes $4: 3$. The quantity of alcohol in the mixture is (in $\text{litres}$):

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