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(A) The potential energy $(P.E.)$ of a particle executing simple harmonic motion is given by the formula: $P.E. = \frac{1}{2}m\omega^2x^2$,where $m$ i

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$ \pm A$

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(A) The potential energy $(P.E.)$ of a particle executing simple harmonic motion is given by the formula: $P.E. = \frac{1}{2}m\omega^2x^2$,where $m$ is the mass,$\omega$ is the angular frequency,and $x$ is the displacement.From the formula,it is clear that the potential energy is directly proportional to the square of the displacement $(x^2)$.Therefore,the potential energy will be maximum when the displacement $x$ is at its maximum value.Since the amplitude of the motion is $A$,the maximum displacement is $x = \pm A$.Thus,the potential energy is maximum at $x = \pm A$.

$A$ particle executes simple harmonic motion along a straight line with an amplitude $A$. The potential energy is maximum when the displacement is

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