A particle has an initial velocity (3hat{i} + | vedclass

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(B) Given:Initial velocity,$\vec{u} = (3\hat{i} + 4\hat{j})\,m/s$Acceleration,$\vec{a} = (0.4\hat{i} + 0.3\hat{j})\,m/s^2$Time,$t = 10\,s$Using the fi

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$7\sqrt{2}$ units

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(B) Given:Initial velocity,$\vec{u} = (3\hat{i} + 4\hat{j})\,m/s$Acceleration,$\vec{a} = (0.4\hat{i} + 0.3\hat{j})\,m/s^2$Time,$t = 10\,s$Using the first equation of motion for vectors:$\vec{v} = \vec{u} + \vec{a}t$$\vec{v} = (3\hat{i} + 4\hat{j}) + (0.4\hat{i} + 0.3\hat{j}) 	imes 10$$\vec{v} = (3\hat{i} + 4\hat{j}) + (4\hat{i} + 3\hat{j})$$\vec{v} = (3+4)\hat{i} + (4+3)\hat{j} = 7\hat{i} + 7\hat{j}$The speed is the magnitude of the velocity vector $\vec{v}$:$|\vec{v}| = \sqrt{(7)^2 + (7)^2}$$|\vec{v}| = \sqrt{49 + 49} = \sqrt{98}$$|\vec{v}| = 7\sqrt{2}$ units.

$A$ particle has an initial velocity $(3\hat{i} + 4\hat{j})$ and an acceleration of $(0.4\hat{i} + 0.3\hat{j})$. Its speed after $10\,s$ is:

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