A particle is projected with speed u at an an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The vertical displacement of the projectile between times $t_1$ and $t_2$ is zero because the particle is at the same height at both times.Average

Vedclass · Accepted Answer

$u \cos 	heta$

Vedclass · Answer

(C) The vertical displacement of the projectile between times $t_1$ and $t_2$ is zero because the particle is at the same height at both times.Average velocity is defined as the total displacement divided by the total time interval.Average velocity $\vec{v}_{avg} = \frac{\Delta \vec{r}}{\Delta t} = \frac{\Delta x \hat{i} + \Delta y \hat{j}}{t_2 - t_1}$.Since the height is the same,$\Delta y = 0$.The horizontal displacement $\Delta x$ is given by $v_x 	imes (t_2 - t_1)$,where $v_x = u \cos 	heta$.Thus,$\Delta x = (u \cos 	heta)(t_2 - t_1)$.Substituting this into the average velocity formula: $\vec{v}_{avg} = \frac{(u \cos 	heta)(t_2 - t_1) \hat{i} + 0 \hat{j}}{t_2 - t_1} = u \cos 	heta \hat{i}$.Therefore,the magnitude of the average velocity is $u \cos 	heta$.

$A$ particle is projected with speed $u$ at an angle $\theta$ with the horizontal from the ground. If it is at the same height from the ground at times $t_1$ and $t_2$,then its average velocity in the time interval $t_1$ to $t_2$ is .........

Similar Questions

$A$ projectile is fired at an angle of $45^{\circ}$ with the horizontal. The elevation angle of the projectile at its highest point as seen from the point of projection is:

Two particles are projected from the same point with the same speed $u$ such that they have the same range $R$,but different maximum heights,$h_1$ and $h_2$. Which of the following is correct?

If the height of a projectile at a time of $2 \ s$ from the beginning of motion is $60 \ m$,then the time of flight of the projectile is (Acceleration due to gravity $= 10 \ m \ s^{-2}$) (in $s$)

$A$ projectile is thrown with a velocity of $50 \, ms^{-1}$ at an angle of $53^o$ with the horizontal. Choose the incorrect statement.

$A$ projectile fired with initial velocity $u$ at an angle $\theta$ has a range $R$. If the initial velocity is doubled at the same angle of projection,then the new range will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module