A projectile is thrown with a velocity of 50 | vedclass

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(D) Given: Initial velocity $u = 50 \, ms^{-1}$,angle $	heta = 53^o$.Horizontal component of velocity: $u_x = u \cos 53^o = 50 	imes (3/5) = 30 \, m

Vedclass · Accepted Answer

None of these.

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(D) Given: Initial velocity $u = 50 \, ms^{-1}$,angle $	heta = 53^o$.Horizontal component of velocity: $u_x = u \cos 53^o = 50 	imes (3/5) = 30 \, ms^{-1}$.Vertical component of velocity: $u_y = u \sin 53^o = 50 	imes (4/5) = 40 \, ms^{-1}$.Statement $A$: The vertical component of velocity at the start is $40 \, ms^{-1}$. This is correct.Statement $B$: The horizontal component of velocity is $30 \, ms^{-1}$. This is correct.Statement $C$: The minimum velocity of a projectile occurs at the highest point,which is equal to the horizontal component $u_x = 30 \, ms^{-1}$. This is correct.Since all statements $A, B,$ and $C$ are correct,the incorrect statement is none of these.

Column-$I$	Column-$II$
$(1)$ Vertical component of velocity is zero	$(a)$ Tangent to the parabolic path
$(2)$ Linear velocity	$(b)$ Maximum height point of the projectile trajectory

$A$ projectile is thrown with a velocity of $50 \, ms^{-1}$ at an angle of $53^o$ with the horizontal. Choose the incorrect statement.

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Match Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Vertical component of velocity is zero $(a)$ Tangent to the parabolic path

$(2)$ Linear velocity $(b)$ Maximum height point of the projectile trajectory

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