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(C) In projectile motion,the horizontal component of velocity remains constant throughout the flight because there is no acceleration in the horizonta

Vedclass · Accepted Answer

$v=u \cos 	heta \sec \phi$

Vedclass · Answer

(C) In projectile motion,the horizontal component of velocity remains constant throughout the flight because there is no acceleration in the horizontal direction.Let the initial velocity be $u$ at an angle $	heta$ with the horizontal. The horizontal component is $u_x = u \cos 	heta$.When the particle is at a point where its velocity is $v$ at an angle $\phi$ with the horizontal,the horizontal component of this velocity is $v_x = v \cos \phi$.Since the horizontal component remains constant,we have $v_x = u_x$.Therefore,$v \cos \phi = u \cos 	heta$.Solving for $v$,we get $v = \frac{u \cos 	heta}{\cos \phi} = u \cos 	heta \sec \phi$.

$A$ particle is thrown with a speed $u$ at an angle $\theta$ with the horizontal. When the particle makes an angle $\phi$ with the horizontal,its speed changes to $v$,where

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