$A$ particle moves along an arc of a circle of radius $R$. Its velocity depends on the distance covered as $v = a\sqrt{s}$,where $a$ is a constant. Then the angle $\alpha$ between the vector of the total acceleration and the vector of velocity as a function of $s$ will be:

  • A
    $\tan \alpha = \frac{R}{2s}$
  • B
    $\tan \alpha = \frac{2s}{R}$
  • C
    $\tan \alpha = \frac{2R}{s}$
  • D
    $\tan \alpha = \frac{s}{2R}$

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