(C) Given that the particle starts from rest,the initial velocity $u = 0$. Since the force is constant,the acceleration $a$ is also constant. The dist

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(C) Given that the particle starts from rest,the initial velocity $u = 0$. Since the force is constant,the acceleration $a$ is also constant. The distance $S$ covered in time $t$ is given by the equation of motion: $S = ut + \frac{1}{2}at^2$. For $t = 10 \ s$,the distance $S_1 = 0(10) + \frac{1}{2}a(10)^2 = 50a$. For $t = 20 \ s$,the distance $S_2 = 0(20) + \frac{1}{2}a(20)^2 = 200a$. Comparing the two,$S_2 = 200a = 4(50a) = 4S_1$. Therefore,$S_2 = 4S_1$.

Class 11 Physics Motion in Straight Line Uniformly Accelerated Motion

Medium

$A$ particle starts its motion from rest under the action of a constant force. If the distance covered in the first $10 \ s$ is $S_1$ and that covered in the first $20 \ s$ is $S_2$,then:

AIPMT 2009 All AIPMT

A
$S_2 = 2S_1$
B
$S_2 = 3S_1$
C
$S_2 = 4S_1$
D
$S_2 = S_1$

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$A$ particle starts its motion from rest under the action of a constant force. If the distance covered in the first $10 \ s$ is $S_1$ and that covered in the first $20 \ s$ is $S_2$,then:

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