A passenger buys 5 tickets for Ahmadabad to N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the probl

Vedclass · Accepted Answer

Cost of ticket for Ahmadabad to Nadiad is Rs. $50$ and for Ahmadabad to Vadodara is Rs. $80$.

Vedclass · Answer

(A) Let the cost of a ticket from Ahmadabad to Nadiad be Rs. $x$ and the cost of a ticket from Ahmadabad to Vadodara be Rs. $y$.According to the problem,we have two equations:$1) 5x + 10y = 1050$Dividing by $5$,we get: $x + 2y = 210$$2) x + y = 130$Subtracting equation $(2)$ from equation $(1)$:$(x + 2y) - (x + y) = 210 - 130$$y = 80$Substituting $y = 80$ into equation $(2)$:$x + 80 = 130$$x = 130 - 80 = 50$Therefore,the cost of a ticket from Ahmadabad to Nadiad is Rs. $50$ and the cost of a ticket from Ahmadabad to Vadodara is Rs. $80$.

Similar Questions

If $4x - 12y = 20$,then $5x - 15y = \ldots$

Solve the following pair of linear equations by the method of substitution: $8x - 3y = 1$ and $34x - 3y = 14$.

Solve the following pair of linear equations: $\frac{9}{a} + \frac{8}{b} = 7$ and $\frac{2}{a} - \frac{3}{b} = -8$.

For eliminating $y$ from the equations $3x - 2y = 1$ and $5x + y = 6$,the second equation should be multiplied by

Vedclass Test Series

Exam Paper Generator

Online Exam Module