A point z moves on the Argand diagram in such | vedclass

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$A$ circle

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(C) The given equation is $|z - 3i| = 2$. Let $z = x + iy$. Substituting $z$ in the equation,we get $|x + iy - 3i| = 2$,which simplifies to $|x + i(y - 3)| = 2$. The modulus of a complex number $a + ib$ is $\sqrt{a^2 + b^2}$. Thus,$\sqrt{x^2 + (y - 3)^2} = 2$. Squaring both sides,we get $x^2 + (y - 3)^2 = 4$. This is the equation of a circle with center $(0, 3)$ and radius $2$. Therefore,the locus is a circle.

$A$ point $z$ moves on the Argand diagram in such a way that $|z - 3i| = 2$. Then its locus will be:

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