A proton moving with a constant velocity pass | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The force on a charged particle moving with velocity $v$ in the presence of electric field $E$ and magnetic field $B$ is given by the Lorentz forc

Vedclass · Accepted Answer

$E=0, B 
eq 0$

Vedclass · Answer

(A) The force on a charged particle moving with velocity $v$ in the presence of electric field $E$ and magnetic field $B$ is given by the Lorentz force equation: $F = q(E + v 	imes B)$.For the velocity to remain constant,the net force $F$ must be zero.$(i)$ If $E=0$ and $B 
eq 0$,the proton can move parallel or anti-parallel to the magnetic field $B$. In this case,the magnetic force $F_m = q(v 	imes B) = 0$ because the angle between $v$ and $B$ is $0^{\circ}$ or $180^{\circ}$. Thus,the velocity remains constant.$(ii)$ If $E 
eq 0$ and $B 
eq 0$,the electric force $F_e = qE$ and magnetic force $F_m = q(v 	imes B)$ can be equal and opposite,such that $F_e + F_m = 0$. This is the principle of a velocity selector.Since the question asks what the region *may* have,and option $A$ $(E=0, B 
eq 0)$ is a valid condition where the proton experiences no force,it is a correct possibility.

$A$ proton moving with a constant velocity passes through a region of space without any change in its velocity. If $E$ and $B$ represent the electric and magnetic fields respectively,this region may have:

Similar Questions

Two particles of masses $m_{a}$ and $m_{b}$ and same charge are projected in a perpendicular magnetic field. They travel along circular paths of radius $r_{a}$ and $r_{b}$ such that $r_{a} > r_{b}$. Then which is true?

If a proton is projected in a direction perpendicular to a uniform magnetic field with velocity $v$ and an electron is projected along the lines of force,what will happen to the proton and electron?

$A$ particle of mass $0.6\, g$ and having a charge of $25\, nC$ is moving horizontally with a uniform velocity $1.2 \times 10^4\, m/s$ in a uniform magnetic field. If the particle continues to move with uniform velocity,the value of the magnetic induction is $(g = 10\, m/s^2)$.

$A$ proton of mass $m$ moving with a speed $v$ ($v << c$, where $c$ is the velocity of light in vacuum) completes a circular orbit in time $T$ in a uniform magnetic field. If the speed of the proton is increased to $\sqrt{2}v$, what will be the time needed to complete the circular orbit?

$H^+$,$He^+$,and $O^{++}$ are projected in a uniform transverse magnetic field with equal accelerating potential. If their masses are $1 \, a.m.u.$,$4 \, a.m.u.$,and $16 \, a.m.u.$ respectively,find the ratio of their radii.

Vedclass Test Series

Exam Paper Generator

Online Exam Module