A ray of light falls on the surface of a sphe | vedclass

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Question

(B) When a light ray enters the spherical glass paperweight at point $A$,it is refracted at an angle $\beta$. The angle of deviation at this point is

Vedclass · Accepted Answer

$2(\alpha - \beta)$

Vedclass · Answer

(B) When a light ray enters the spherical glass paperweight at point $A$,it is refracted at an angle $\beta$. The angle of deviation at this point is $\delta_1 = (\alpha - \beta)$.At the point of emergence $B$,the ray strikes the surface at an angle $\beta$ (due to the symmetry of the isosceles triangle formed by the radii) and emerges at an angle $\alpha$. The angle of deviation at this point is $\delta_2 = (\alpha - \beta)$.The total angle of deviation $\delta$ is the sum of the deviations at both surfaces:$\delta = \delta_1 + \delta_2 = (\alpha - \beta) + (\alpha - \beta) = 2(\alpha - \beta)$.

$A$ ray of light falls on the surface of a spherical glass paperweight,making an angle $\alpha$ with the normal,and is refracted in the medium at an angle $\beta$. What is the angle of deviation of the emergent ray from the direction of the incident ray?

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