A ray of light strikes a plane mirror M at an | vedclass

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(C) The total deviation produced by the system is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviati

Vedclass · Accepted Answer

$92$

Vedclass · Answer

(C) The total deviation produced by the system is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviation by the mirror: When a light ray strikes a plane mirror at an angle of incidence $i$,the deviation produced is $\delta_{	ext{mirror}} = 180^{\circ} - 2i$.Given $i = 45^{\circ}$,$\delta_{	ext{mirror}} = 180^{\circ} - 2(45^{\circ}) = 180^{\circ} - 90^{\circ} = 90^{\circ}$.$2$. Deviation by the prism: For a thin prism with small apex angle $A$ and refractive index $\mu$,the deviation is $\delta_{	ext{prism}} = (\mu - 1)A$.Given $\mu = 1.5$ and $A = 4^{\circ}$,$\delta_{	ext{prism}} = (1.5 - 1) 	imes 4^{\circ} = 0.5 	imes 4^{\circ} = 2^{\circ}$.$3$. Total deviation: $\delta_{	ext{net}} = \delta_{	ext{mirror}} + \delta_{	ext{prism}} = 90^{\circ} + 2^{\circ} = 92^{\circ}$.

$A$ ray of light strikes a plane mirror $M$ at an angle of $45^{\circ}$ as shown in the figure. After reflection,the ray passes through a prism of refractive index $1.5$ whose apex angle is $4^{\circ}$. The total angle through which the ray is deviated is......$^{\circ}$

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