A rope,by which a horse is tied,is increased | vedclass

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(C) The area grazed by the horse is the area of a circle with the rope length as the radius.Initial radius $r = 12 \ m$.Final radius $R = 23 \ m$.The

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$1210$

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(C) The area grazed by the horse is the area of a circle with the rope length as the radius.Initial radius $r = 12 \ m$.Final radius $R = 23 \ m$.The additional area grazed is the area of the annulus (the region between two concentric circles) given by $\pi R^2 - \pi r^2 = \pi(R^2 - r^2) = \pi(R+r)(R-r)$.Using $\pi = \frac{22}{7}$:Additional area $= \frac{22}{7} 	imes (23 + 12) 	imes (23 - 12) \ m^2$$= \frac{22}{7} 	imes 35 	imes 11 \ m^2$$= 22 	imes 5 	imes 11 \ m^2$$= 110 	imes 11 \ m^2$$= 1210 \ m^2$.

$A$ rope,by which a horse is tied,is increased from $12 \ m$ to $23 \ m$. How much additional ground will it be able to graze? (in $m^2$)

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