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(B) The formula for bulk modulus $(B)$ is given by $B = -\frac{\Delta P}{\Delta V / V} = -\frac{V \Delta P}{\Delta V}$.Given:Initial volume $V = 1.5\,

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$1.05 	imes 10^9\,Pa$

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(B) The formula for bulk modulus $(B)$ is given by $B = -\frac{\Delta P}{\Delta V / V} = -\frac{V \Delta P}{\Delta V}$.Given:Initial volume $V = 1.5\,L = 1.5 	imes 10^{-3}\,m^3$.Change in pressure $\Delta P = 140\,kPa = 140 	imes 10^3\,Pa$.Change in volume $\Delta V = -0.2\,mL = -0.2 	imes 10^{-6}\,m^3$.Substituting the values into the formula:$B = -\frac{1.5 	imes 10^{-3} 	imes 140 	imes 10^3}{-0.2 	imes 10^{-6}}$$B = \frac{210}{0.2 	imes 10^{-6}} = 1050 	imes 10^6\,Pa = 1.05 	imes 10^9\,Pa$.

$A$ sample of a liquid has an initial volume of $1.5\,L$. The volume is reduced by $0.2\,mL$ when the pressure increases by $140\,kPa$. What is the bulk modulus of the liquid?

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