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(D) The total energy of a satellite in a circular orbit is given by $E = -\frac{GMm}{2r}$.When the satellite loses energy,its total energy $E$ becomes

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$r$ will decrease and $v$ will increase

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(D) The total energy of a satellite in a circular orbit is given by $E = -\frac{GMm}{2r}$.When the satellite loses energy,its total energy $E$ becomes more negative (i.e.,decreases).Since $E = -\frac{GMm}{2r}$,for $E$ to decrease (become more negative),the radius $r$ must decrease.As the satellite moves to a lower orbit (smaller $r$),the gravitational potential energy decreases,and the kinetic energy increases to satisfy the orbital velocity condition $v = \sqrt{\frac{GM}{r}}$.Therefore,as $r$ decreases,the orbital speed $v$ increases.

$A$ satellite moving around the Earth in a circular orbit of radius $r$ and speed $v$ suddenly loses some of its energy. Then

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