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(D) The number density of silicon atoms is given as $5 	imes 10^{28} 	ext{ atoms } m^{-3}$.Since $1 	ext{ m} = 100 	ext{ cm}$,$1 	ext{ m}^3 = 10^

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$1 	imes 10^{15} 	ext{ atoms } cm^{-3}$

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(D) The number density of silicon atoms is given as $5 	imes 10^{28} 	ext{ atoms } m^{-3}$.Since $1 	ext{ m} = 100 	ext{ cm}$,$1 	ext{ m}^3 = 10^6 	ext{ cm}^3$.Therefore,the number density in $cm^{-3}$ is $\frac{5 	imes 10^{28}}{10^6} = 5 	imes 10^{22} 	ext{ atoms } cm^{-3}$.Given that $1$ indium atom is doped per $5 	imes 10^7$ silicon atoms,the concentration of acceptor atoms $(n_A)$ is calculated as:$n_A = \frac{	ext{Total silicon atoms per } cm^3}{5 	imes 10^7} = \frac{5 	imes 10^{22}}{5 	imes 10^7} = 10^{15} 	ext{ atoms } cm^{-3}$.

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