$A$ square $ABCD$ of diagonal $2a$ is folded along the diagonal $AC$ so that the planes $DAC$ and $BAC$ are at a right angle. The shortest distance between $DC$ and $AB$ is

  • A
    $\sqrt{2}a$
  • B
    $2a/\sqrt{3}$
  • C
    $2a/\sqrt{5}$
  • D
    $(\sqrt{3}/2)a$

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