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(B) The reaction involves the selective reduction of a ketone group to an alcohol group in the presence of a nitro group $(-NO_2)$.$NaBH_4$ (Sodium bo

Vedclass · Accepted Answer

$NaBH_4$

Vedclass · Answer

(B) The reaction involves the selective reduction of a ketone group to an alcohol group in the presence of a nitro group $(-NO_2)$.$NaBH_4$ (Sodium borohydride) is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce the nitro group $(-NO_2)$.$LiAlH_4$ and $H_2/Ni$ are strong reducing agents that would reduce both the ketone and the nitro group.Therefore,$NaBH_4$ is the correct reagent.

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