Among the following compounds,the one that is | vedclass

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(A) $1$. $BF_3$ has a trigonal planar geometry with $sp^2$ hybridization,but it is non-polar due to the cancellation of dipole moments.$2$. $SiF_4$ ha

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$H_2CO_3$

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(A) $1$. $BF_3$ has a trigonal planar geometry with $sp^2$ hybridization,but it is non-polar due to the cancellation of dipole moments.$2$. $SiF_4$ has a tetrahedral geometry with $sp^3$ hybridization and is non-polar.$3$. $HClO_2$ has a central $Cl$ atom with $sp^3$ hybridization.$4$. $H_2CO_3$ (carbonic acid) has a central carbon atom with $sp^2$ hybridization. Due to the asymmetric arrangement of atoms and the difference in electronegativity between $C$,$O$,and $H$,the molecule is polar.

Among the following compounds,the one that is polar and has a central atom with $sp^2$ hybridization is:

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