An AC current is given by I = I_{1} sin omega | vedclass

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(B) The given current is $I = I_{1} \sin \omega t + I_{2} \cos \omega t$.This can be rewritten in the form $I = I_{0} \sin(\omega t + \phi)$,where $I_

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$\sqrt{\frac{I_{1}^{2}+I_{2}^{2}}{2}}$

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(B) The given current is $I = I_{1} \sin \omega t + I_{2} \cos \omega t$.This can be rewritten in the form $I = I_{0} \sin(\omega t + \phi)$,where $I_{0}$ is the peak current.The amplitude $I_{0}$ is given by $\sqrt{I_{1}^{2} + I_{2}^{2}}$.$A$ hot wire ammeter measures the root mean square $(RMS)$ value of the current.The $RMS$ value is defined as $I_{rms} = \frac{I_{0}}{\sqrt{2}}$.Substituting the value of $I_{0}$,we get $I_{rms} = \sqrt{\frac{I_{1}^{2} + I_{2}^{2}}{2}}$.

An $AC$ current is given by $I = I_{1} \sin \omega t + I_{2} \cos \omega t$. $A$ hot wire ammeter will give a reading of:

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