An alternating current is flowing through a s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a series $L-C-R$ circuit, the current is the same at two different frequencies $f_1$ and $f_2$ if these frequencies are equidistant from the re

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(D) In a series $L-C-R$ circuit, the current is the same at two different frequencies $f_1$ and $f_2$ if these frequencies are equidistant from the resonance frequency $f_0$ in a geometric sense.The resonance frequency $f_0$ is given by the geometric mean of the two frequencies at which the current is equal:$f_0 = \sqrt{f_1 	imes f_2}$Given:$f_1 = 200 \ Hz$$f_2 = 800 \ Hz$Substituting the values:$f_0 = \sqrt{200 	imes 800}$$f_0 = \sqrt{160000}$$f_0 = 400 \ Hz$Thus, the resonance frequency of the circuit is $400 \ Hz$.

An alternating current is flowing through a series $L-C-R$ circuit. It is found that the current reaches a value of $1 \ mA$ at both $200 \ Hz$ and $800 \ Hz$ frequency. What is the resonance frequency of the circuit (in $Hz$)?

Similar Questions

In a series $LCR$ circuit at resonance,the phase difference between voltage and current is

When resonance is produced in a series $LCR$ circuit,then which of the following is not correct?

The current in resistance $R$ at resonance is

In an $LCR$ circuit,the resonating frequency is $500 \,kHz$. If the value of $L$ is doubled and the value of $C$ is decreased to $\frac{1}{8}$ times its initial value,then the new resonating frequency in $kHz$ will be .......

In a series resonant circuit, the $AC$ voltages across resistance $R$, inductor $L$, and capacitor $C$ are $5 \,V$, $10 \,V$, and $10 \,V$ respectively. The $AC$ voltage applied to the circuit will be . . . . . . . (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module