An alternating e.m.f. is given as $e = e_0 \sin \omega t$. In what time will the e.m.f. have half its maximum value if $e$ starts from zero?
$(T = \text{time period}, \sin 30^{\circ} = \cos 60^{\circ} = 0.5)$
$(T = \text{time period}, \sin 30^{\circ} = \cos 60^{\circ} = 0.5)$
- A$\frac{T}{12}$
- B$\frac{T}{8}$
- C$\frac{T}{16}$
- D$\frac{T}{4}$
Explore More
Similar Questions
For an $AC$ current $I = 50 \cos(100t + 45^{\circ}) \ A$. The value of $I_{rms} =$ . . . . . . $A$.
In an $ac$ circuit,the $r.m.s.$ value of current,$I_{rms}$ is related to the peak current,$I_0$ by the relation:
Easy
View SolutionWhat is the $r.m.s.$ value of the current $i = t^2$ for the time interval $0 < t < T$?
Medium
View SolutionThe frequency of $AC$ mains in India is (in $\text{ Hz}$)
The instantaneous values of current and voltage in an $AC$ circuit are given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$ and $V = 5 \sin(100 \pi t - \frac{\pi}{4})$. Then,
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo