In an $ac$ circuit,the $r.m.s.$ value of current,$I_{rms}$ is related to the peak current,$I_0$ by the relation:

  • A
    $I_{rms} = \frac{1}{\pi} I_0$
  • B
    $I_{rms} = \frac{1}{\sqrt{2}} I_0$
  • C
    $I_{rms} = \sqrt{2} I_0$
  • D
    $I_{rms} = \pi I_0$

Explore More

Similar Questions

The direct current which would give the same heating effect in an equal constant resistance as the current shown in the figure,i.e.,the $r.m.s.$ current,is.....$A$

In an $AC$ circuit,the peak value of voltage is $423 \ V$. Its effective voltage is .......... $V$.

An alternating e.m.f. is given by $e = e_{0} \sin(\omega t)$. In what time will the e.m.f. reach half its maximum value,if $e$ starts from zero? ($T$ = Time period)

The phase difference between the voltage and the current in an $AC$ circuit is $\pi / 4$. If the frequency is $50 \ Hz$,then this phase difference will be equivalent to a time of:

If an alternating voltage is represented as $E = 141 \sin(628 t)$,then the rms value of the voltage and the frequency are respectively:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo