An electric heater draws a current of 2;A whe | vedclass

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(A) According to Ohm's Law,the relationship between voltage $(V)$,current $(I)$,and resistance $(R)$ is given by the formula $V = I 	imes R$.Given va

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$60\;\Omega$

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(A) According to Ohm's Law,the relationship between voltage $(V)$,current $(I)$,and resistance $(R)$ is given by the formula $V = I 	imes R$.Given values are:Voltage $(V)$ = $120\;V$Current $(I)$ = $2\;A$To find the resistance $(R)$,we rearrange the formula: $R = V / I$.Substituting the values: $R = 120\;V / 2\;A = 60\;\Omega$.Therefore,the resistance of the heater coil is $60\;\Omega$.

An electric heater draws a current of $2\;A$ when connected to a voltage source of $120\;V$. What is the resistance of the heater coil?

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