An electromagnetic wave travelling in a lossl | vedclass

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(B) Given: $\epsilon_r = 9$, $\omega = 2\pi 	imes 10^6 	ext{ rad/s}$.
$1$. Speed of wave in medium: $v = \frac{c}{\sqrt{\epsilon_r}} = \frac{3 	ime

Vedclass · Accepted Answer

The wavelength of the electromagnetic wave inside the medium is $300 	ext{ m}$

Vedclass · Answer

(B) Given: $\epsilon_r = 9$, $\omega = 2\pi 	imes 10^6 	ext{ rad/s}$.
$1$. Speed of wave in medium: $v = \frac{c}{\sqrt{\epsilon_r}} = \frac{3 	imes 10^8}{3} = 10^8 	ext{ ms}^{-1}$. Option $(1)$ is correct.
$2$. Wavelength in medium: $\lambda = \frac{v}{f} = \frac{10^8}{10^6} = 100 	ext{ m}$. Option $(2)$ states $300 	ext{ m}$, which is incorrect.
$3$. Magnetic field relation: $B_0 = \frac{E_0}{v}$, so $B_y = \frac{E_0}{v} \sin(kz - \omega t)$. Option $(3)$ is conceptually correct in its form.
$4$. Propagation direction: The phase is $(kz - \omega t)$, which indicates propagation along $+z$. Option $(4)$ is correct.
Thus, the incorrect choice is $(2)$.

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