An electron in a stationary hydrogen atom jumps from the $4^{\text{th}}$ energy level to the ground level. The velocity that the photon acquired as a result of the electron transition will be ($h=$ Planck's constant,$R=$ Rydberg's constant,$m=$ mass of the photon).
- A$\frac{11 R h}{16 m}$
- B$\frac{15 R h}{16 m}$
- C$\frac{9 R h}{16 m}$
- D$\frac{13 R h}{16 m}$
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{ $R =$ Rydberg constant,$m =$ mass of hydrogen atom }
{ $R =$ Rydberg constant,$m =$ mass of hydrogen atom }
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