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(B) The charge of the nucleus of a hydrogen atom is $q_1 = +e$.The charge of the electron is $q_2 = -e$.The Coulomb force $\vec{F}$ is given by the fo

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$-k \frac{e^2}{r^3} \vec{r}$

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(B) The charge of the nucleus of a hydrogen atom is $q_1 = +e$.The charge of the electron is $q_2 = -e$.The Coulomb force $\vec{F}$ is given by the formula $\vec{F} = \frac{k q_1 q_2}{r^2} \hat{r}$,where $\hat{r}$ is the unit vector pointing from the nucleus to the electron.Substituting the values,we get $\vec{F} = \frac{k(e)(-e)}{r^2} \hat{r} = -\frac{k e^2}{r^2} \hat{r}$.Since $\hat{r} = \frac{\vec{r}}{r}$,we can rewrite the expression as $\vec{F} = -\frac{k e^2}{r^2} \left( \frac{\vec{r}}{r} \right) = -k \frac{e^2}{r^3} \vec{r}$.

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius $r$. The Coulomb force $\vec{F}$ between the two is

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