An ideal gas goes through a reversible cycle | vedclass

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(A) In the given $V - T$ diagram:$1$. Process $a 	o b$: The line passes through the origin,so $V \propto T$. From the ideal gas law $PV = nRT$,this i

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(A) In the given $V - T$ diagram:$1$. Process $a 	o b$: The line passes through the origin,so $V \propto T$. From the ideal gas law $PV = nRT$,this implies $P$ is constant. Thus,$a 	o b$ is an isobaric process where temperature increases,meaning volume also increases.$2$. Process $b 	o c$: This is given as an adiabatic process. Since $V$ decreases and $T$ increases (from the graph),the pressure $P$ must increase significantly.$3$. Process $c 	o d$: The line passes through the origin,so $V \propto T$,which implies $P$ is constant. Thus,$c 	o d$ is an isobaric process where temperature decreases,meaning volume also decreases.$4$. Process $d 	o a$: This is given as an adiabatic process. Since $V$ increases and $T$ decreases (from the graph),the pressure $P$ must decrease.Comparing these characteristics with the given options,the $P - V$ diagram that correctly represents these processes is Option $A$.

Column $I$	Column $II$
$(A)$ An insulated container has two chambers separated by a valve. Chamber $I$ contains an ideal gas and Chamber $II$ has a vacuum. The valve is opened.	$(p)$ The temperature of the gas decreases
$(B)$ An ideal monoatomic gas expands to twice its original volume such that its pressure $P \propto V^{-2}$	$(q)$ The temperature of the gas increases or remains constant
$(C)$ An ideal monoatomic gas expands to twice its original volume such that its pressure $P \propto V^{-4/3}$	$(r)$ The gas loses heat
$(D)$ An ideal monoatomic gas expands such that its pressure $P$ and volume $V$ follow the behavior shown in the graph	$(s)$ The gas gains heat

An ideal gas goes through a reversible cycle $a \to b \to c \to d$ and has the $V - T$ diagram shown below. Processes $d \to a$ and $b \to c$ are adiabatic. The corresponding $P - V$ diagram for the process is (all figures are schematic and not drawn to scale):

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