An iron rod is placed parallel to a magnetic field of intensity $H = 2000 \text{ A/m}$. The magnetic flux through the rod is $\phi = 6 \times 10^{-4} \text{ Wb}$ and its cross-sectional area is $A = 3 \text{ cm}^2$. The magnetic permeability $\mu$ of the rod in $\text{Wb/A} \cdot \text{m}$ is:

  • A
    $10^{-1}$
  • B
    $10^{-2}$
  • C
    $10^{-3}$
  • D
    $10^{-4}$

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