An organic compound (X) has an empirical form | vedclass

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Question

(B) The empirical formula is $C_4H_8O$. The compound $(X)$ gives a pale yellow precipitate with iodine in $NaOH$ solution,which indicates the presence

Vedclass · Accepted Answer

$CH_2=CHCH(OH)CH_3$

Vedclass · Answer

(B) The empirical formula is $C_4H_8O$. The compound $(X)$ gives a pale yellow precipitate with iodine in $NaOH$ solution,which indicates the presence of a methyl ketone group or a secondary alcohol that can be oxidized to a methyl ketone (iodoform test). Among the options,$CH_2=CHCH(OH)CH_3$ is a secondary alcohol. Upon oxidation,it forms $CH_2=CHCOCH_3$ (methyl vinyl ketone),which contains a methyl ketone group $(CH_3CO-)$ and thus gives a positive iodoform test. The reaction is: $CH_2=CHCH(OH)CH_3$ $\xrightarrow{	ext{Oxidation}} CH_2=CHCOCH_3$ $\xrightarrow{I_2/NaOH} CHI_3 + CH_2=CHCOO^-Na^+$.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

An organic compound $(X)$ has an empirical formula $C_4H_8O$. This gives a pale yellow precipitate with iodine in $NaOH$ solution. What is $X$?

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The product $(Q)$ will be:

The test to differentiate between $\text{pentan-2-one}$ and $\text{pentan-3-one}$ is

Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

Identify $A$ in the following reaction: $A + CH_3MgBr$ $\xrightarrow{\text{ether}} \text{complex}$ $\xrightarrow{H_3O^{+}} (CH_3)_3C-OH$

In the given reaction,what will be $A$ and $B$ respectively?
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$

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