An organic compound having molecular formula $C_2H_6O$ undergoes oxidation with $K_2Cr_2O_7 / H_2SO_4$ to produce $X$ which contains $40\,\%$ carbon,$6.7\,\%$ hydrogen and $53.3\,\%$ oxygen. The molecular formula of the compound $X$ is

  • A
    $CH_2O$
  • B
    $C_2H_4O_2$
  • C
    $C_2H_4O$
  • D
    $C_2H_6O_2$

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