The angle of a prism is 10^o. The refractive | vedclass

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(B) The dispersive power $\omega$ is given by the formula: $\omega = \frac{\mu_{v} - \mu_{R}}{\mu_{y} - 1}$.Here,$\mu_{v} = 1.52$ and $\mu_{R} = 1.51$

Vedclass · Accepted Answer

$0.019$

Vedclass · Answer

(B) The dispersive power $\omega$ is given by the formula: $\omega = \frac{\mu_{v} - \mu_{R}}{\mu_{y} - 1}$.Here,$\mu_{v} = 1.52$ and $\mu_{R} = 1.51$.The mean refractive index $\mu_{y}$ is calculated as: $\mu_{y} = \frac{\mu_{v} + \mu_{R}}{2} = \frac{1.52 + 1.51}{2} = 1.515$.Now,substituting these values into the formula for dispersive power:$\omega = \frac{1.52 - 1.51}{1.515 - 1} = \frac{0.01}{0.515}$.$\omega \approx 0.0194$.Rounding to three decimal places,we get $\omega = 0.019$.

The angle of a prism is $10^o$. The refractive indices for red and violet colours are $1.51$ and $1.52$ respectively. Find the dispersive power.

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