Arrange the following carbocations in increas | vedclass

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Question

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the positively charged carbon atom.$(I)$ $CH

Vedclass · Accepted Answer

$IV < II < III < I$

Vedclass · Answer

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the positively charged carbon atom.$(I)$ $CH_3O-C_6H_4-CH_2^+$: The $-OCH_3$ group exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the carbocation.$(II)$ $C_6H_5-CH_2^+$: This is a benzyl carbocation,stabilized by resonance with the benzene ring.$(III)$ $CH_3-C_6H_4-CH_2^+$: The $-CH_3$ group exerts a $+I$ (inductive) effect and hyperconjugation,providing moderate stabilization.$(IV)$ $CH_3-CH_2-CH_2^+$: This is a primary alkyl carbocation,which is the least stable among the given options.Comparing these,the order of stability is: $IV < II < III < I$.

Column $-I$	Column $-II$
$A$. Free radical	$1$. Trigonal planar
$B$. Carbocation	$2$. Pyramidal
$C$. Carbanion	$3$. Linear

Arrange the following carbocations in increasing order of stability:

Similar Questions

The number of hyperconjugation structures involved to stabilize the carbocation formed in the above reaction is $.............$.

Which of the following is the least stable carbocation?

Match the intermediates given in Column $-I$ with their probable structure in Column $-II$.

Column $-I$ Column $-II$

$A$. Free radical $1$. Trigonal planar

$B$. Carbocation $2$. Pyramidal

$C$. Carbanion $3$. Linear

Which of the following is the electrophile involved in the given reaction?

The most stable carbonium ion among the following is:

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