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(A) The acidic strength of phenols depends on the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)

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$ii < iii < iv < i$

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(A) The acidic strength of phenols depends on the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)$ stabilize the phenoxide ion and increase acidity,while electron-donating groups $(EDG)$ destabilize it and decrease acidity.$1$. $m-$cresol $(ii)$: The $-CH_3$ group is an $EDG$ due to $+I$ effect and hyperconjugation,making it less acidic than phenol.$2$. Phenol $(iii)$: The reference compound.$3$. $m-$chlorophenol $(iv)$: The $-Cl$ group is an $EWG$ due to its strong $-I$ effect,which outweighs its $+R$ effect at the meta position,making it more acidic than phenol.$4$. $m-$nitrophenol $(i)$: The $-NO_2$ group is a strong $EWG$ due to both $-I$ and $-R$ effects,making it the most acidic among the given compounds.Thus,the increasing order of acidic strength is: $m-$cresol $(ii)$ The correct option is $A$.

List-$I$ (Reactants)	List-$II$ (Products)
$A$. Phenol,$Zn / \Delta$	$I$. Salicylaldehyde
$B$. Phenol,$CHCl_3, NaOH, HCl$	$II$. Salicylic acid
$C$. Phenol,$CO_2, NaOH, HCl$	$III$. Benzene
$D$. Phenol,Conc. $HNO_3$	$IV$. Picric acid

Arrange the following compounds in the increasing order of their acidic strength :
$i$. $m-$nitrophenol
$ii$. $m-$cresol
$iii$. phenol
$iv$. $m-$chlorophenol

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List-$I$ (Reactants) List-$II$ (Products)

$A$. Phenol,$Zn / \Delta$ $I$. Salicylaldehyde

$B$. Phenol,$CHCl_3, NaOH, HCl$ $II$. Salicylic acid

$C$. Phenol,$CO_2, NaOH, HCl$ $III$. Benzene

$D$. Phenol,Conc. $HNO_3$ $IV$. Picric acid

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Arrange the following compounds in the increasing order of their acidic strength :$i$. $m-$nitrophenol$ii$. $m-$cresol$iii$. phenol$iv$. $m-$chlorophenol