Arrange the following in increasing order of their basic strength:
$(i)$ $C_2H_5NH_2, C_6H_5NH_2, NH_3, C_6H_5CH_2NH_2$ and $(C_2H_5)_2NH$
$(ii)$ $C_2H_5NH_2, (C_2H_5)_2NH, (C_2H_5)_3N, C_6H_5NH_2$
$(iii)$ $CH_3NH_2, (CH_3)_2NH, (CH_3)_3N, C_6H_5NH_2, C_6H_5CH_2NH_2$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ Considering the inductive effect of alkyl groups,the basic strength order is $C_6H_5NH_2 < NH_3 < C_6H_5CH_2NH_2 < C_2H_5NH_2 < (C_2H_5)_2NH$.
$(ii)$ Considering the inductive effect,solvation effect,and steric hindrance of the alkyl groups in aqueous medium,the order is $C_6H_5NH_2 < C_2H_5NH_2 < (C_2H_5)_3N < (C_2H_5)_2NH$.
$(iii)$ Considering the inductive effect,solvation effect,and steric hindrance of the methyl groups in aqueous medium,the order is $C_6H_5NH_2 < C_6H_5CH_2NH_2 < (CH_3)_3N < CH_3NH_2 < (CH_3)_2NH$.

Explore More

Similar Questions

Arrange the following in the order of their basic strength:

Nitration of aniline in a strong acidic medium also gives $m$-nitroaniline because

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

$Ph-C(=O)-OH$ $\xrightarrow{NH_3, \Delta} (A)$ $\xrightarrow{Br_2, KOH} (B)$,product $(B)$ is:

Difficult
View Solution

In the case of substituted aniline,the group which decreases the basic strength is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo