Assertion : Acetylene on reacting with sodami | vedclass

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(A) Acetylene reacts with sodamide $(NaNH_2)$ to form sodium acetylide and ammonia.$CH\equiv CH + NaNH_2 \rightarrow HC\equiv C^{-}Na^{+} + NH_3$This

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) Acetylene reacts with sodamide $(NaNH_2)$ to form sodium acetylide and ammonia.$CH\equiv CH + NaNH_2 \rightarrow HC\equiv C^{-}Na^{+} + NH_3$This reaction occurs because the $sp$ hybridized carbon atoms in acetylene have $50\%$ $s$-character.Due to the high $s$-character,the electrons are held more tightly by the nucleus,making the carbon atom significantly electronegative.This increased electronegativity makes the terminal hydrogen atom acidic,allowing it to be replaced by the sodium ion from the sodamide.Therefore,both the Assertion and the Reason are correct,and the Reason is the correct explanation of the Assertion.

Assertion : Acetylene on reacting with sodamide gives sodium acetylide and ammonia.
Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.

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Assertion : Acetylene on reacting with sodamide gives sodium acetylide and ammonia.Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.