Assuming that the junction diode is ideal, find the current in the arrangement shown in the figure. (in $\text{mA}$)

  • A
    $2$
  • B
    $20$
  • C
    $30$
  • D
    $10$

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The circuit contains two diodes,each with a forward resistance of $50\, \Omega$ and an infinite reverse resistance. If the battery voltage is $6\, V$,the current through the $120\, \Omega$ resistance is $mA$.

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